Integrand size = 28, antiderivative size = 159 \[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=-\frac {8 \sqrt [4]{-1} a^3 \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{d^{9/2} f}-\frac {32 i a^3}{35 d^2 f (d \tan (e+f x))^{5/2}}+\frac {8 a^3}{3 d^3 f (d \tan (e+f x))^{3/2}}+\frac {8 i a^3}{d^4 f \sqrt {d \tan (e+f x)}}-\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}} \]
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Time = 0.35 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {3634, 3672, 3610, 3614, 211} \[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=-\frac {8 \sqrt [4]{-1} a^3 \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{d^{9/2} f}+\frac {8 i a^3}{d^4 f \sqrt {d \tan (e+f x)}}+\frac {8 a^3}{3 d^3 f (d \tan (e+f x))^{3/2}}-\frac {32 i a^3}{35 d^2 f (d \tan (e+f x))^{5/2}}-\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}} \]
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Rule 211
Rule 3610
Rule 3614
Rule 3634
Rule 3672
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}}-\frac {2 \int \frac {(a+i a \tan (e+f x)) \left (-8 i a^2 d+6 a^2 d \tan (e+f x)\right )}{(d \tan (e+f x))^{7/2}} \, dx}{7 d^2} \\ & = -\frac {32 i a^3}{35 d^2 f (d \tan (e+f x))^{5/2}}-\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}}-\frac {2 \int \frac {14 a^3 d^2+14 i a^3 d^2 \tan (e+f x)}{(d \tan (e+f x))^{5/2}} \, dx}{7 d^4} \\ & = -\frac {32 i a^3}{35 d^2 f (d \tan (e+f x))^{5/2}}+\frac {8 a^3}{3 d^3 f (d \tan (e+f x))^{3/2}}-\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}}-\frac {2 \int \frac {14 i a^3 d^3-14 a^3 d^3 \tan (e+f x)}{(d \tan (e+f x))^{3/2}} \, dx}{7 d^6} \\ & = -\frac {32 i a^3}{35 d^2 f (d \tan (e+f x))^{5/2}}+\frac {8 a^3}{3 d^3 f (d \tan (e+f x))^{3/2}}+\frac {8 i a^3}{d^4 f \sqrt {d \tan (e+f x)}}-\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}}-\frac {2 \int \frac {-14 a^3 d^4-14 i a^3 d^4 \tan (e+f x)}{\sqrt {d \tan (e+f x)}} \, dx}{7 d^8} \\ & = -\frac {32 i a^3}{35 d^2 f (d \tan (e+f x))^{5/2}}+\frac {8 a^3}{3 d^3 f (d \tan (e+f x))^{3/2}}+\frac {8 i a^3}{d^4 f \sqrt {d \tan (e+f x)}}-\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}}-\frac {\left (112 a^6\right ) \text {Subst}\left (\int \frac {1}{-14 a^3 d^5+14 i a^3 d^4 x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{f} \\ & = -\frac {8 \sqrt [4]{-1} a^3 \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{d^{9/2} f}-\frac {32 i a^3}{35 d^2 f (d \tan (e+f x))^{5/2}}+\frac {8 a^3}{3 d^3 f (d \tan (e+f x))^{3/2}}+\frac {8 i a^3}{d^4 f \sqrt {d \tan (e+f x)}}-\frac {2 \left (a^3+i a^3 \tan (e+f x)\right )}{7 d f (d \tan (e+f x))^{7/2}} \\ \end{align*}
Time = 3.09 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.62 \[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=-\frac {2 a^3 \left (420 \sqrt [4]{-1} \sqrt {d} \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )+\frac {d \left (-420 i-140 \cot (e+f x)+63 i \cot ^2(e+f x)+15 \cot ^3(e+f x)\right )}{\sqrt {d \tan (e+f x)}}\right )}{105 d^5 f} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 340 vs. \(2 (132 ) = 264\).
Time = 0.85 (sec) , antiderivative size = 341, normalized size of antiderivative = 2.14
method | result | size |
derivativedivides | \(\frac {2 a^{3} \left (\frac {\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{2 d}+\frac {i \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{2 \left (d^{2}\right )^{\frac {1}{4}}}}{d^{2}}-\frac {3 i}{5 \left (d \tan \left (f x +e \right )\right )^{\frac {5}{2}}}-\frac {d}{7 \left (d \tan \left (f x +e \right )\right )^{\frac {7}{2}}}+\frac {4 i}{d^{2} \sqrt {d \tan \left (f x +e \right )}}+\frac {4}{3 d \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}\right )}{f \,d^{2}}\) | \(341\) |
default | \(\frac {2 a^{3} \left (\frac {\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{2 d}+\frac {i \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{2 \left (d^{2}\right )^{\frac {1}{4}}}}{d^{2}}-\frac {3 i}{5 \left (d \tan \left (f x +e \right )\right )^{\frac {5}{2}}}-\frac {d}{7 \left (d \tan \left (f x +e \right )\right )^{\frac {7}{2}}}+\frac {4 i}{d^{2} \sqrt {d \tan \left (f x +e \right )}}+\frac {4}{3 d \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}\right )}{f \,d^{2}}\) | \(341\) |
parts | \(\frac {2 a^{3} d \left (-\frac {1}{7 d^{2} \left (d \tan \left (f x +e \right )\right )^{\frac {7}{2}}}+\frac {1}{3 d^{4} \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}+\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 d^{6}}\right )}{f}-\frac {2 i a^{3} \left (-\frac {\sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 d^{2} \left (d^{2}\right )^{\frac {1}{4}}}-\frac {1}{d^{2} \sqrt {d \tan \left (f x +e \right )}}\right )}{f \,d^{2}}+\frac {3 i a^{3} \left (-\frac {2}{5 d^{2} \left (d \tan \left (f x +e \right )\right )^{\frac {5}{2}}}+\frac {2}{d^{4} \sqrt {d \tan \left (f x +e \right )}}+\frac {\sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{4 d^{4} \left (d^{2}\right )^{\frac {1}{4}}}\right )}{f}-\frac {6 a^{3} \left (-\frac {1}{3 d^{2} \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}-\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 d^{4}}\right )}{f d}\) | \(673\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 521 vs. \(2 (131) = 262\).
Time = 0.26 (sec) , antiderivative size = 521, normalized size of antiderivative = 3.28 \[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=\frac {105 \, {\left (d^{5} f e^{\left (8 i \, f x + 8 i \, e\right )} - 4 \, d^{5} f e^{\left (6 i \, f x + 6 i \, e\right )} + 6 \, d^{5} f e^{\left (4 i \, f x + 4 i \, e\right )} - 4 \, d^{5} f e^{\left (2 i \, f x + 2 i \, e\right )} + d^{5} f\right )} \sqrt {-\frac {64 i \, a^{6}}{d^{9} f^{2}}} \log \left (\frac {{\left (-8 i \, a^{3} d e^{\left (2 i \, f x + 2 i \, e\right )} + {\left (d^{5} f e^{\left (2 i \, f x + 2 i \, e\right )} + d^{5} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {64 i \, a^{6}}{d^{9} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{4 \, a^{3}}\right ) - 105 \, {\left (d^{5} f e^{\left (8 i \, f x + 8 i \, e\right )} - 4 \, d^{5} f e^{\left (6 i \, f x + 6 i \, e\right )} + 6 \, d^{5} f e^{\left (4 i \, f x + 4 i \, e\right )} - 4 \, d^{5} f e^{\left (2 i \, f x + 2 i \, e\right )} + d^{5} f\right )} \sqrt {-\frac {64 i \, a^{6}}{d^{9} f^{2}}} \log \left (\frac {{\left (-8 i \, a^{3} d e^{\left (2 i \, f x + 2 i \, e\right )} - {\left (d^{5} f e^{\left (2 i \, f x + 2 i \, e\right )} + d^{5} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {64 i \, a^{6}}{d^{9} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{4 \, a^{3}}\right ) - 16 \, {\left (319 \, a^{3} e^{\left (8 i \, f x + 8 i \, e\right )} - 327 \, a^{3} e^{\left (6 i \, f x + 6 i \, e\right )} - 95 \, a^{3} e^{\left (4 i \, f x + 4 i \, e\right )} + 387 \, a^{3} e^{\left (2 i \, f x + 2 i \, e\right )} - 164 \, a^{3}\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}}{420 \, {\left (d^{5} f e^{\left (8 i \, f x + 8 i \, e\right )} - 4 \, d^{5} f e^{\left (6 i \, f x + 6 i \, e\right )} + 6 \, d^{5} f e^{\left (4 i \, f x + 4 i \, e\right )} - 4 \, d^{5} f e^{\left (2 i \, f x + 2 i \, e\right )} + d^{5} f\right )}} \]
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\[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=- i a^{3} \left (\int \frac {i}{\left (d \tan {\left (e + f x \right )}\right )^{\frac {9}{2}}}\, dx + \int \left (- \frac {3 \tan {\left (e + f x \right )}}{\left (d \tan {\left (e + f x \right )}\right )^{\frac {9}{2}}}\right )\, dx + \int \frac {\tan ^{3}{\left (e + f x \right )}}{\left (d \tan {\left (e + f x \right )}\right )^{\frac {9}{2}}}\, dx + \int \left (- \frac {3 i \tan ^{2}{\left (e + f x \right )}}{\left (d \tan {\left (e + f x \right )}\right )^{\frac {9}{2}}}\right )\, dx\right ) \]
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Time = 0.29 (sec) , antiderivative size = 235, normalized size of antiderivative = 1.48 \[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=\frac {\frac {105 \, a^{3} {\left (\frac {\left (2 i + 2\right ) \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {d} + 2 \, \sqrt {d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {d}}\right )}{\sqrt {d}} + \frac {\left (2 i + 2\right ) \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {d} - 2 \, \sqrt {d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {d}}\right )}{\sqrt {d}} - \frac {\left (i - 1\right ) \, \sqrt {2} \log \left (d \tan \left (f x + e\right ) + \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {d} + d\right )}{\sqrt {d}} + \frac {\left (i - 1\right ) \, \sqrt {2} \log \left (d \tan \left (f x + e\right ) - \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {d} + d\right )}{\sqrt {d}}\right )}}{d^{3}} - \frac {2 \, {\left (-420 i \, a^{3} d^{3} \tan \left (f x + e\right )^{3} - 140 \, a^{3} d^{3} \tan \left (f x + e\right )^{2} + 63 i \, a^{3} d^{3} \tan \left (f x + e\right ) + 15 \, a^{3} d^{3}\right )}}{\left (d \tan \left (f x + e\right )\right )^{\frac {7}{2}} d^{3}}}{105 \, d f} \]
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Time = 1.15 (sec) , antiderivative size = 150, normalized size of antiderivative = 0.94 \[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=\frac {8 i \, \sqrt {2} a^{3} \arctan \left (\frac {8 \, \sqrt {d^{2}} \sqrt {d \tan \left (f x + e\right )}}{4 i \, \sqrt {2} d^{\frac {3}{2}} + 4 \, \sqrt {2} \sqrt {d^{2}} \sqrt {d}}\right )}{d^{\frac {9}{2}} f {\left (\frac {i \, d}{\sqrt {d^{2}}} + 1\right )}} - \frac {2 \, {\left (-420 i \, a^{3} d^{3} \tan \left (f x + e\right )^{3} - 140 \, a^{3} d^{3} \tan \left (f x + e\right )^{2} + 63 i \, a^{3} d^{3} \tan \left (f x + e\right ) + 15 \, a^{3} d^{3}\right )}}{105 \, \sqrt {d \tan \left (f x + e\right )} d^{7} f \tan \left (f x + e\right )^{3}} \]
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Time = 5.90 (sec) , antiderivative size = 119, normalized size of antiderivative = 0.75 \[ \int \frac {(a+i a \tan (e+f x))^3}{(d \tan (e+f x))^{9/2}} \, dx=-\frac {\frac {2\,a^3}{7\,d\,f}+\frac {a^3\,\mathrm {tan}\left (e+f\,x\right )\,6{}\mathrm {i}}{5\,d\,f}-\frac {8\,a^3\,{\mathrm {tan}\left (e+f\,x\right )}^2}{3\,d\,f}-\frac {a^3\,{\mathrm {tan}\left (e+f\,x\right )}^3\,8{}\mathrm {i}}{d\,f}}{{\left (d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{7/2}}+\frac {\sqrt {16{}\mathrm {i}}\,a^3\,\mathrm {atan}\left (\frac {\sqrt {16{}\mathrm {i}}\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{4\,\sqrt {-d}}\right )\,2{}\mathrm {i}}{{\left (-d\right )}^{9/2}\,f} \]
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